What is the molar mass of iron ii sulfate feso4


Asked by wiki @ in Chemistry viewed by 53 People


What mass of FeSO4^2- x 6H20 (Molar Mass=260g/mol) is required to produce 500 mL of a .10M iron (II) sulfate solution.

A.) 9g
B.) 13g
C.) 36g
D.) 72g

Answered by wiki @


Answer:

The correct option is: B. 13g

Explanation:

Given: Molar mass of iron (II) sulfate: m = 260g/mol,

Molarity of iron (II) sulfate solution: M =  0.1 M,

Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L           (∵ 1L = 1000mL)

Mass of iron (II) sulfate taken: w = ? g

Molarity: M = \frac{n}{V (L)} = \frac{w}{m\times V(L)}

Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L

Molarity of iron (II) sulfate solution:  M = \frac{w}{m\times V(L)}

⇒  w = M\times m\times V(L)

⇒  w = (0.1 M)\times (260g/mol)\times (0.5L)

⇒  mass of iron (II) sulfate taken: w = 13 g

Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.

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